A rock is thrown vertically upward from the ground with an initial speed 15m/s.
a. how high does it go
b. how much time is required for the rock to reach its maximum height?
c. what is the rock’s height at t=2.00s?
(Posted by Merhawi)
Answer:
(a)
u=15m/s
a=-10m/s2
v=0 m/s (at the max height)
S=?
v2-u2=2aS
S=v2-u2/2a
=225/20
=11.25 m
(b) From the above case
using v=u+at
t=v-u/a=1.5s
(c) Use S = ut + 1/2 at2
put t=2s, u = 15m/s, a=-10m/s2
S=30 – 20 = 10 m
(If you use g = 9.8 m/s2 The answers will be slightly different)
Incoming search terms:
- Is anger physical quantity
- kinematics passing question
- a rock is thrown up with speed of 15
- ques of kinematics
- physics problem of the day
- physics (what is conservation of momentum?)
- maximum height of a rock thrown
- distance on electron due to gravity
- A rock is thrown vertically upward from the ground with an initial speed
- rock thrown vertically physics equation
Link to this post!
The problem of a rock thrown vertically up" onclick="javascript:this.select()" readonly="readonly" style="width: 100%;" />